3.2.7 \(\int \frac {(a+a \sin (e+f x))^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx\) [107]

3.2.7.1 Optimal result
3.2.7.2 Mathematica [C] (verified)
3.2.7.3 Rubi [A] (verified)
3.2.7.4 Maple [B] (verified)
3.2.7.5 Fricas [B] (verification not implemented)
3.2.7.6 Sympy [F(-1)]
3.2.7.7 Maxima [F]
3.2.7.8 Giac [B] (verification not implemented)
3.2.7.9 Mupad [F(-1)]

3.2.7.1 Optimal result

Integrand size = 38, antiderivative size = 266 \[ \int \frac {(a+a \sin (e+f x))^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx=-\frac {a^3 (3 A-17 B) \text {arctanh}\left (\frac {\sqrt {c} \cos (e+f x)}{\sqrt {2} \sqrt {c-c \sin (e+f x)}}\right )}{512 \sqrt {2} c^{11/2} f}+\frac {a^3 (A+B) c^3 \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}+\frac {a^3 (3 A-17 B) c \cos ^5(e+f x)}{80 f (c-c \sin (e+f x))^{13/2}}-\frac {a^3 (3 A-17 B) \cos ^3(e+f x)}{96 c f (c-c \sin (e+f x))^{9/2}}+\frac {a^3 (3 A-17 B) \cos (e+f x)}{128 c^3 f (c-c \sin (e+f x))^{5/2}}-\frac {a^3 (3 A-17 B) \cos (e+f x)}{512 c^4 f (c-c \sin (e+f x))^{3/2}} \]

output
1/10*a^3*(A+B)*c^3*cos(f*x+e)^7/f/(c-c*sin(f*x+e))^(17/2)+1/80*a^3*(3*A-17 
*B)*c*cos(f*x+e)^5/f/(c-c*sin(f*x+e))^(13/2)-1/96*a^3*(3*A-17*B)*cos(f*x+e 
)^3/c/f/(c-c*sin(f*x+e))^(9/2)+1/128*a^3*(3*A-17*B)*cos(f*x+e)/c^3/f/(c-c* 
sin(f*x+e))^(5/2)-1/512*a^3*(3*A-17*B)*cos(f*x+e)/c^4/f/(c-c*sin(f*x+e))^( 
3/2)-1/1024*a^3*(3*A-17*B)*arctanh(1/2*cos(f*x+e)*c^(1/2)*2^(1/2)/(c-c*sin 
(f*x+e))^(1/2))/c^(11/2)/f*2^(1/2)
 
3.2.7.2 Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 15.20 (sec) , antiderivative size = 409, normalized size of antiderivative = 1.54 \[ \int \frac {(a+a \sin (e+f x))^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx=\frac {a^3 \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right ) (1+\sin (e+f x))^3 \left (56370 A \cos \left (\frac {1}{2} (e+f x)\right )+38970 B \cos \left (\frac {1}{2} (e+f x)\right )-31140 A \cos \left (\frac {3}{2} (e+f x)\right )-38580 B \cos \left (\frac {3}{2} (e+f x)\right )-10404 A \cos \left (\frac {5}{2} (e+f x)\right )-12724 B \cos \left (\frac {5}{2} (e+f x)\right )+435 A \cos \left (\frac {7}{2} (e+f x)\right )+7775 B \cos \left (\frac {7}{2} (e+f x)\right )-45 A \cos \left (\frac {9}{2} (e+f x)\right )+255 B \cos \left (\frac {9}{2} (e+f x)\right )+(240+240 i) \sqrt [4]{-1} (3 A-17 B) \arctan \left (\left (\frac {1}{2}+\frac {i}{2}\right ) \sqrt [4]{-1} \left (1+\tan \left (\frac {1}{4} (e+f x)\right )\right )\right ) \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )^{10}+56370 A \sin \left (\frac {1}{2} (e+f x)\right )+38970 B \sin \left (\frac {1}{2} (e+f x)\right )+31140 A \sin \left (\frac {3}{2} (e+f x)\right )+38580 B \sin \left (\frac {3}{2} (e+f x)\right )-10404 A \sin \left (\frac {5}{2} (e+f x)\right )-12724 B \sin \left (\frac {5}{2} (e+f x)\right )-435 A \sin \left (\frac {7}{2} (e+f x)\right )-7775 B \sin \left (\frac {7}{2} (e+f x)\right )-45 A \sin \left (\frac {9}{2} (e+f x)\right )+255 B \sin \left (\frac {9}{2} (e+f x)\right )\right )}{122880 f \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^6 (c-c \sin (e+f x))^{11/2}} \]

input
Integrate[((a + a*Sin[e + f*x])^3*(A + B*Sin[e + f*x]))/(c - c*Sin[e + f*x 
])^(11/2),x]
 
output
(a^3*(Cos[(e + f*x)/2] - Sin[(e + f*x)/2])*(1 + Sin[e + f*x])^3*(56370*A*C 
os[(e + f*x)/2] + 38970*B*Cos[(e + f*x)/2] - 31140*A*Cos[(3*(e + f*x))/2] 
- 38580*B*Cos[(3*(e + f*x))/2] - 10404*A*Cos[(5*(e + f*x))/2] - 12724*B*Co 
s[(5*(e + f*x))/2] + 435*A*Cos[(7*(e + f*x))/2] + 7775*B*Cos[(7*(e + f*x)) 
/2] - 45*A*Cos[(9*(e + f*x))/2] + 255*B*Cos[(9*(e + f*x))/2] + (240 + 240* 
I)*(-1)^(1/4)*(3*A - 17*B)*ArcTan[(1/2 + I/2)*(-1)^(1/4)*(1 + Tan[(e + f*x 
)/4])]*(Cos[(e + f*x)/2] - Sin[(e + f*x)/2])^10 + 56370*A*Sin[(e + f*x)/2] 
 + 38970*B*Sin[(e + f*x)/2] + 31140*A*Sin[(3*(e + f*x))/2] + 38580*B*Sin[( 
3*(e + f*x))/2] - 10404*A*Sin[(5*(e + f*x))/2] - 12724*B*Sin[(5*(e + f*x)) 
/2] - 435*A*Sin[(7*(e + f*x))/2] - 7775*B*Sin[(7*(e + f*x))/2] - 45*A*Sin[ 
(9*(e + f*x))/2] + 255*B*Sin[(9*(e + f*x))/2]))/(122880*f*(Cos[(e + f*x)/2 
] + Sin[(e + f*x)/2])^6*(c - c*Sin[e + f*x])^(11/2))
 
3.2.7.3 Rubi [A] (verified)

Time = 1.29 (sec) , antiderivative size = 255, normalized size of antiderivative = 0.96, number of steps used = 16, number of rules used = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.395, Rules used = {3042, 3446, 3042, 3338, 3042, 3159, 3042, 3159, 3042, 3159, 3042, 3129, 3042, 3128, 219}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(a \sin (e+f x)+a)^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {(a \sin (e+f x)+a)^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}}dx\)

\(\Big \downarrow \) 3446

\(\displaystyle a^3 c^3 \int \frac {\cos ^6(e+f x) (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{17/2}}dx\)

\(\Big \downarrow \) 3042

\(\displaystyle a^3 c^3 \int \frac {\cos (e+f x)^6 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{17/2}}dx\)

\(\Big \downarrow \) 3338

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \int \frac {\cos ^6(e+f x)}{(c-c \sin (e+f x))^{15/2}}dx}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \int \frac {\cos (e+f x)^6}{(c-c \sin (e+f x))^{15/2}}dx}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3159

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \int \frac {\cos ^4(e+f x)}{(c-c \sin (e+f x))^{11/2}}dx}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \int \frac {\cos (e+f x)^4}{(c-c \sin (e+f x))^{11/2}}dx}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3159

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \left (\frac {\cos ^3(e+f x)}{3 c f (c-c \sin (e+f x))^{9/2}}-\frac {\int \frac {\cos ^2(e+f x)}{(c-c \sin (e+f x))^{7/2}}dx}{2 c^2}\right )}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \left (\frac {\cos ^3(e+f x)}{3 c f (c-c \sin (e+f x))^{9/2}}-\frac {\int \frac {\cos (e+f x)^2}{(c-c \sin (e+f x))^{7/2}}dx}{2 c^2}\right )}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3159

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \left (\frac {\cos ^3(e+f x)}{3 c f (c-c \sin (e+f x))^{9/2}}-\frac {\frac {\cos (e+f x)}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {\int \frac {1}{(c-c \sin (e+f x))^{3/2}}dx}{4 c^2}}{2 c^2}\right )}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \left (\frac {\cos ^3(e+f x)}{3 c f (c-c \sin (e+f x))^{9/2}}-\frac {\frac {\cos (e+f x)}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {\int \frac {1}{(c-c \sin (e+f x))^{3/2}}dx}{4 c^2}}{2 c^2}\right )}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3129

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \left (\frac {\cos ^3(e+f x)}{3 c f (c-c \sin (e+f x))^{9/2}}-\frac {\frac {\cos (e+f x)}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {\frac {\int \frac {1}{\sqrt {c-c \sin (e+f x)}}dx}{4 c}+\frac {\cos (e+f x)}{2 f (c-c \sin (e+f x))^{3/2}}}{4 c^2}}{2 c^2}\right )}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \left (\frac {\cos ^3(e+f x)}{3 c f (c-c \sin (e+f x))^{9/2}}-\frac {\frac {\cos (e+f x)}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {\frac {\int \frac {1}{\sqrt {c-c \sin (e+f x)}}dx}{4 c}+\frac {\cos (e+f x)}{2 f (c-c \sin (e+f x))^{3/2}}}{4 c^2}}{2 c^2}\right )}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 3128

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \left (\frac {\cos ^3(e+f x)}{3 c f (c-c \sin (e+f x))^{9/2}}-\frac {\frac {\cos (e+f x)}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {\frac {\cos (e+f x)}{2 f (c-c \sin (e+f x))^{3/2}}-\frac {\int \frac {1}{2 c-\frac {c^2 \cos ^2(e+f x)}{c-c \sin (e+f x)}}d\left (-\frac {c \cos (e+f x)}{\sqrt {c-c \sin (e+f x)}}\right )}{2 c f}}{4 c^2}}{2 c^2}\right )}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

\(\Big \downarrow \) 219

\(\displaystyle a^3 c^3 \left (\frac {(3 A-17 B) \left (\frac {\cos ^5(e+f x)}{4 c f (c-c \sin (e+f x))^{13/2}}-\frac {5 \left (\frac {\cos ^3(e+f x)}{3 c f (c-c \sin (e+f x))^{9/2}}-\frac {\frac {\cos (e+f x)}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {\frac {\text {arctanh}\left (\frac {\sqrt {c} \cos (e+f x)}{\sqrt {2} \sqrt {c-c \sin (e+f x)}}\right )}{2 \sqrt {2} c^{3/2} f}+\frac {\cos (e+f x)}{2 f (c-c \sin (e+f x))^{3/2}}}{4 c^2}}{2 c^2}\right )}{8 c^2}\right )}{20 c}+\frac {(A+B) \cos ^7(e+f x)}{10 f (c-c \sin (e+f x))^{17/2}}\right )\)

input
Int[((a + a*Sin[e + f*x])^3*(A + B*Sin[e + f*x]))/(c - c*Sin[e + f*x])^(11 
/2),x]
 
output
a^3*c^3*(((A + B)*Cos[e + f*x]^7)/(10*f*(c - c*Sin[e + f*x])^(17/2)) + ((3 
*A - 17*B)*(Cos[e + f*x]^5/(4*c*f*(c - c*Sin[e + f*x])^(13/2)) - (5*(Cos[e 
 + f*x]^3/(3*c*f*(c - c*Sin[e + f*x])^(9/2)) - (Cos[e + f*x]/(2*c*f*(c - c 
*Sin[e + f*x])^(5/2)) - (ArcTanh[(Sqrt[c]*Cos[e + f*x])/(Sqrt[2]*Sqrt[c - 
c*Sin[e + f*x]])]/(2*Sqrt[2]*c^(3/2)*f) + Cos[e + f*x]/(2*f*(c - c*Sin[e + 
 f*x])^(3/2)))/(4*c^2))/(2*c^2)))/(8*c^2)))/(20*c))
 

3.2.7.3.1 Defintions of rubi rules used

rule 219
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3128
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[-2/d 
Subst[Int[1/(2*a - x^2), x], x, b*(Cos[c + d*x]/Sqrt[a + b*Sin[c + d*x]])], 
 x] /; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0]
 

rule 3129
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[b*Cos[c 
+ d*x]*((a + b*Sin[c + d*x])^n/(a*d*(2*n + 1))), x] + Simp[(n + 1)/(a*(2*n 
+ 1))   Int[(a + b*Sin[c + d*x])^(n + 1), x], x] /; FreeQ[{a, b, c, d}, x] 
&& EqQ[a^2 - b^2, 0] && LtQ[n, -1] && IntegerQ[2*n]
 

rule 3159
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x 
_)])^(m_), x_Symbol] :> Simp[2*g*(g*Cos[e + f*x])^(p - 1)*((a + b*Sin[e + f 
*x])^(m + 1)/(b*f*(2*m + p + 1))), x] + Simp[g^2*((p - 1)/(b^2*(2*m + p + 1 
)))   Int[(g*Cos[e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 2), x], x] /; 
FreeQ[{a, b, e, f, g}, x] && EqQ[a^2 - b^2, 0] && LeQ[m, -2] && GtQ[p, 1] & 
& NeQ[2*m + p + 1, 0] &&  !ILtQ[m + p + 1, 0] && IntegersQ[2*m, 2*p]
 

rule 3338
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x 
_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(b*c - 
 a*d)*(g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^m/(a*f*g*(2*m + p + 1) 
)), x] + Simp[(a*d*m + b*c*(m + p + 1))/(a*b*(2*m + p + 1))   Int[(g*Cos[e 
+ f*x])^p*(a + b*Sin[e + f*x])^(m + 1), x], x] /; FreeQ[{a, b, c, d, e, f, 
g, m, p}, x] && EqQ[a^2 - b^2, 0] && (LtQ[m, -1] || ILtQ[Simplify[m + p], 0 
]) && NeQ[2*m + p + 1, 0]
 

rule 3446
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + 
 (f_.)*(x_)])*((c_) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Si 
mp[a^m*c^m   Int[Cos[e + f*x]^(2*m)*(c + d*Sin[e + f*x])^(n - m)*(A + B*Sin 
[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && EqQ[b*c + a* 
d, 0] && EqQ[a^2 - b^2, 0] && IntegerQ[m] &&  !(IntegerQ[n] && ((LtQ[m, 0] 
&& GtQ[n, 0]) || LtQ[0, n, m] || LtQ[m, n, 0]))
 
3.2.7.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(525\) vs. \(2(235)=470\).

Time = 5.05 (sec) , antiderivative size = 526, normalized size of antiderivative = 1.98

method result size
default \(\frac {a^{3} \left (15 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c +c \sin \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) c^{6} \left (3 A -17 B \right ) \left (\cos ^{4}\left (f x +e \right )\right ) \sin \left (f x +e \right )-75 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c +c \sin \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) c^{6} \left (3 A -17 B \right ) \left (\cos ^{4}\left (f x +e \right )\right )-180 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c +c \sin \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) c^{6} \left (3 A -17 B \right ) \left (\cos ^{2}\left (f x +e \right )\right ) \sin \left (f x +e \right )+300 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c +c \sin \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) c^{6} \left (3 A -17 B \right ) \left (\cos ^{2}\left (f x +e \right )\right )+240 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c +c \sin \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) c^{6} \left (3 A -17 B \right ) \sin \left (f x +e \right )-90 A \left (c +c \sin \left (f x +e \right )\right )^{\frac {9}{2}} c^{\frac {3}{2}}+840 A \left (c +c \sin \left (f x +e \right )\right )^{\frac {7}{2}} c^{\frac {5}{2}}+3072 A \left (c +c \sin \left (f x +e \right )\right )^{\frac {5}{2}} c^{\frac {7}{2}}-3360 A \left (c +c \sin \left (f x +e \right )\right )^{\frac {3}{2}} c^{\frac {9}{2}}+1440 A \sqrt {c +c \sin \left (f x +e \right )}\, c^{\frac {11}{2}}+510 B \left (c +c \sin \left (f x +e \right )\right )^{\frac {9}{2}} c^{\frac {3}{2}}+5480 B \left (c +c \sin \left (f x +e \right )\right )^{\frac {7}{2}} c^{\frac {5}{2}}-17408 B \left (c +c \sin \left (f x +e \right )\right )^{\frac {5}{2}} c^{\frac {7}{2}}+19040 B \left (c +c \sin \left (f x +e \right )\right )^{\frac {3}{2}} c^{\frac {9}{2}}-8160 B \sqrt {c +c \sin \left (f x +e \right )}\, c^{\frac {11}{2}}-720 A \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c +c \sin \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) c^{6}+4080 B \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c +c \sin \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right ) c^{6}\right ) \sqrt {c \left (1+\sin \left (f x +e \right )\right )}}{15360 c^{\frac {23}{2}} \left (\sin \left (f x +e \right )-1\right )^{4} \cos \left (f x +e \right ) \sqrt {c -c \sin \left (f x +e \right )}\, f}\) \(526\)
parts \(\text {Expression too large to display}\) \(1807\)

input
int((a+a*sin(f*x+e))^3*(A+B*sin(f*x+e))/(c-c*sin(f*x+e))^(11/2),x,method=_ 
RETURNVERBOSE)
 
output
1/15360*a^3*(15*2^(1/2)*arctanh(1/2*(c+c*sin(f*x+e))^(1/2)*2^(1/2)/c^(1/2) 
)*c^6*(3*A-17*B)*cos(f*x+e)^4*sin(f*x+e)-75*2^(1/2)*arctanh(1/2*(c+c*sin(f 
*x+e))^(1/2)*2^(1/2)/c^(1/2))*c^6*(3*A-17*B)*cos(f*x+e)^4-180*2^(1/2)*arct 
anh(1/2*(c+c*sin(f*x+e))^(1/2)*2^(1/2)/c^(1/2))*c^6*(3*A-17*B)*cos(f*x+e)^ 
2*sin(f*x+e)+300*2^(1/2)*arctanh(1/2*(c+c*sin(f*x+e))^(1/2)*2^(1/2)/c^(1/2 
))*c^6*(3*A-17*B)*cos(f*x+e)^2+240*2^(1/2)*arctanh(1/2*(c+c*sin(f*x+e))^(1 
/2)*2^(1/2)/c^(1/2))*c^6*(3*A-17*B)*sin(f*x+e)-90*A*(c+c*sin(f*x+e))^(9/2) 
*c^(3/2)+840*A*(c+c*sin(f*x+e))^(7/2)*c^(5/2)+3072*A*(c+c*sin(f*x+e))^(5/2 
)*c^(7/2)-3360*A*(c+c*sin(f*x+e))^(3/2)*c^(9/2)+1440*A*(c+c*sin(f*x+e))^(1 
/2)*c^(11/2)+510*B*(c+c*sin(f*x+e))^(9/2)*c^(3/2)+5480*B*(c+c*sin(f*x+e))^ 
(7/2)*c^(5/2)-17408*B*(c+c*sin(f*x+e))^(5/2)*c^(7/2)+19040*B*(c+c*sin(f*x+ 
e))^(3/2)*c^(9/2)-8160*B*(c+c*sin(f*x+e))^(1/2)*c^(11/2)-720*A*2^(1/2)*arc 
tanh(1/2*(c+c*sin(f*x+e))^(1/2)*2^(1/2)/c^(1/2))*c^6+4080*B*2^(1/2)*arctan 
h(1/2*(c+c*sin(f*x+e))^(1/2)*2^(1/2)/c^(1/2))*c^6)*(c*(1+sin(f*x+e)))^(1/2 
)/c^(23/2)/(sin(f*x+e)-1)^4/cos(f*x+e)/(c-c*sin(f*x+e))^(1/2)/f
 
3.2.7.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 760 vs. \(2 (235) = 470\).

Time = 0.29 (sec) , antiderivative size = 760, normalized size of antiderivative = 2.86 \[ \int \frac {(a+a \sin (e+f x))^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx=-\frac {15 \, \sqrt {2} {\left ({\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{6} - 5 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{5} - 18 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{4} + 20 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{3} + 48 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{2} - 16 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right ) - 32 \, {\left (3 \, A - 17 \, B\right )} a^{3} + {\left ({\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{5} + 6 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{4} - 12 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{3} - 32 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{2} + 16 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right ) + 32 \, {\left (3 \, A - 17 \, B\right )} a^{3}\right )} \sin \left (f x + e\right )\right )} \sqrt {c} \log \left (-\frac {c \cos \left (f x + e\right )^{2} + 2 \, \sqrt {2} \sqrt {-c \sin \left (f x + e\right ) + c} \sqrt {c} {\left (\cos \left (f x + e\right ) + \sin \left (f x + e\right ) + 1\right )} + 3 \, c \cos \left (f x + e\right ) + {\left (c \cos \left (f x + e\right ) - 2 \, c\right )} \sin \left (f x + e\right ) + 2 \, c}{\cos \left (f x + e\right )^{2} + {\left (\cos \left (f x + e\right ) + 2\right )} \sin \left (f x + e\right ) - \cos \left (f x + e\right ) - 2}\right ) - 4 \, {\left (15 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{5} - 5 \, {\left (39 \, A + 803 \, B\right )} a^{3} \cos \left (f x + e\right )^{4} + 4 \, {\left (609 \, A + 389 \, B\right )} a^{3} \cos \left (f x + e\right )^{3} + 12 \, {\left (449 \, A + 869 \, B\right )} a^{3} \cos \left (f x + e\right )^{2} - 24 \, {\left (143 \, A + 43 \, B\right )} a^{3} \cos \left (f x + e\right ) - 6144 \, {\left (A + B\right )} a^{3} + {\left (15 \, {\left (3 \, A - 17 \, B\right )} a^{3} \cos \left (f x + e\right )^{4} + 80 \, {\left (3 \, A + 47 \, B\right )} a^{3} \cos \left (f x + e\right )^{3} + 12 \, {\left (223 \, A + 443 \, B\right )} a^{3} \cos \left (f x + e\right )^{2} - 24 \, {\left (113 \, A + 213 \, B\right )} a^{3} \cos \left (f x + e\right ) - 6144 \, {\left (A + B\right )} a^{3}\right )} \sin \left (f x + e\right )\right )} \sqrt {-c \sin \left (f x + e\right ) + c}}{30720 \, {\left (c^{6} f \cos \left (f x + e\right )^{6} - 5 \, c^{6} f \cos \left (f x + e\right )^{5} - 18 \, c^{6} f \cos \left (f x + e\right )^{4} + 20 \, c^{6} f \cos \left (f x + e\right )^{3} + 48 \, c^{6} f \cos \left (f x + e\right )^{2} - 16 \, c^{6} f \cos \left (f x + e\right ) - 32 \, c^{6} f + {\left (c^{6} f \cos \left (f x + e\right )^{5} + 6 \, c^{6} f \cos \left (f x + e\right )^{4} - 12 \, c^{6} f \cos \left (f x + e\right )^{3} - 32 \, c^{6} f \cos \left (f x + e\right )^{2} + 16 \, c^{6} f \cos \left (f x + e\right ) + 32 \, c^{6} f\right )} \sin \left (f x + e\right )\right )}} \]

input
integrate((a+a*sin(f*x+e))^3*(A+B*sin(f*x+e))/(c-c*sin(f*x+e))^(11/2),x, a 
lgorithm="fricas")
 
output
-1/30720*(15*sqrt(2)*((3*A - 17*B)*a^3*cos(f*x + e)^6 - 5*(3*A - 17*B)*a^3 
*cos(f*x + e)^5 - 18*(3*A - 17*B)*a^3*cos(f*x + e)^4 + 20*(3*A - 17*B)*a^3 
*cos(f*x + e)^3 + 48*(3*A - 17*B)*a^3*cos(f*x + e)^2 - 16*(3*A - 17*B)*a^3 
*cos(f*x + e) - 32*(3*A - 17*B)*a^3 + ((3*A - 17*B)*a^3*cos(f*x + e)^5 + 6 
*(3*A - 17*B)*a^3*cos(f*x + e)^4 - 12*(3*A - 17*B)*a^3*cos(f*x + e)^3 - 32 
*(3*A - 17*B)*a^3*cos(f*x + e)^2 + 16*(3*A - 17*B)*a^3*cos(f*x + e) + 32*( 
3*A - 17*B)*a^3)*sin(f*x + e))*sqrt(c)*log(-(c*cos(f*x + e)^2 + 2*sqrt(2)* 
sqrt(-c*sin(f*x + e) + c)*sqrt(c)*(cos(f*x + e) + sin(f*x + e) + 1) + 3*c* 
cos(f*x + e) + (c*cos(f*x + e) - 2*c)*sin(f*x + e) + 2*c)/(cos(f*x + e)^2 
+ (cos(f*x + e) + 2)*sin(f*x + e) - cos(f*x + e) - 2)) - 4*(15*(3*A - 17*B 
)*a^3*cos(f*x + e)^5 - 5*(39*A + 803*B)*a^3*cos(f*x + e)^4 + 4*(609*A + 38 
9*B)*a^3*cos(f*x + e)^3 + 12*(449*A + 869*B)*a^3*cos(f*x + e)^2 - 24*(143* 
A + 43*B)*a^3*cos(f*x + e) - 6144*(A + B)*a^3 + (15*(3*A - 17*B)*a^3*cos(f 
*x + e)^4 + 80*(3*A + 47*B)*a^3*cos(f*x + e)^3 + 12*(223*A + 443*B)*a^3*co 
s(f*x + e)^2 - 24*(113*A + 213*B)*a^3*cos(f*x + e) - 6144*(A + B)*a^3)*sin 
(f*x + e))*sqrt(-c*sin(f*x + e) + c))/(c^6*f*cos(f*x + e)^6 - 5*c^6*f*cos( 
f*x + e)^5 - 18*c^6*f*cos(f*x + e)^4 + 20*c^6*f*cos(f*x + e)^3 + 48*c^6*f* 
cos(f*x + e)^2 - 16*c^6*f*cos(f*x + e) - 32*c^6*f + (c^6*f*cos(f*x + e)^5 
+ 6*c^6*f*cos(f*x + e)^4 - 12*c^6*f*cos(f*x + e)^3 - 32*c^6*f*cos(f*x + e) 
^2 + 16*c^6*f*cos(f*x + e) + 32*c^6*f)*sin(f*x + e))
 
3.2.7.6 Sympy [F(-1)]

Timed out. \[ \int \frac {(a+a \sin (e+f x))^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx=\text {Timed out} \]

input
integrate((a+a*sin(f*x+e))**3*(A+B*sin(f*x+e))/(c-c*sin(f*x+e))**(11/2),x)
 
output
Timed out
 
3.2.7.7 Maxima [F]

\[ \int \frac {(a+a \sin (e+f x))^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx=\int { \frac {{\left (B \sin \left (f x + e\right ) + A\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{3}}{{\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac {11}{2}}} \,d x } \]

input
integrate((a+a*sin(f*x+e))^3*(A+B*sin(f*x+e))/(c-c*sin(f*x+e))^(11/2),x, a 
lgorithm="maxima")
 
output
integrate((B*sin(f*x + e) + A)*(a*sin(f*x + e) + a)^3/(-c*sin(f*x + e) + c 
)^(11/2), x)
 
3.2.7.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 990 vs. \(2 (235) = 470\).

Time = 0.56 (sec) , antiderivative size = 990, normalized size of antiderivative = 3.72 \[ \int \frac {(a+a \sin (e+f x))^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx=\text {Too large to display} \]

input
integrate((a+a*sin(f*x+e))^3*(A+B*sin(f*x+e))/(c-c*sin(f*x+e))^(11/2),x, a 
lgorithm="giac")
 
output
-1/245760*(120*sqrt(2)*(3*A*a^3*sqrt(c) - 17*B*a^3*sqrt(c))*log(-(cos(-1/4 
*pi + 1/2*f*x + 1/2*e) - 1)/(cos(-1/4*pi + 1/2*f*x + 1/2*e) + 1))/(c^6*sgn 
(sin(-1/4*pi + 1/2*f*x + 1/2*e))) - sqrt(2)*(6*A*a^3*sqrt(c) + 6*B*a^3*sqr 
t(c) + 15*A*a^3*sqrt(c)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) - 1)/(cos(-1/4*pi 
+ 1/2*f*x + 1/2*e) + 1) + 75*B*a^3*sqrt(c)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) 
 - 1)/(cos(-1/4*pi + 1/2*f*x + 1/2*e) + 1) - 30*A*a^3*sqrt(c)*(cos(-1/4*pi 
 + 1/2*f*x + 1/2*e) - 1)^2/(cos(-1/4*pi + 1/2*f*x + 1/2*e) + 1)^2 + 290*B* 
a^3*sqrt(c)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) - 1)^2/(cos(-1/4*pi + 1/2*f*x 
+ 1/2*e) + 1)^2 - 120*A*a^3*sqrt(c)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) - 1)^3 
/(cos(-1/4*pi + 1/2*f*x + 1/2*e) + 1)^3 + 360*B*a^3*sqrt(c)*(cos(-1/4*pi + 
 1/2*f*x + 1/2*e) - 1)^3/(cos(-1/4*pi + 1/2*f*x + 1/2*e) + 1)^3 + 60*A*a^3 
*sqrt(c)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) - 1)^4/(cos(-1/4*pi + 1/2*f*x + 1 
/2*e) + 1)^4 - 900*B*a^3*sqrt(c)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) - 1)^4/(c 
os(-1/4*pi + 1/2*f*x + 1/2*e) + 1)^4 + 822*A*a^3*sqrt(c)*(cos(-1/4*pi + 1/ 
2*f*x + 1/2*e) - 1)^5/(cos(-1/4*pi + 1/2*f*x + 1/2*e) + 1)^5 - 4658*B*a^3* 
sqrt(c)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) - 1)^5/(cos(-1/4*pi + 1/2*f*x + 1/ 
2*e) + 1)^5)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) + 1)^5/(c^6*(cos(-1/4*pi + 1/ 
2*f*x + 1/2*e) - 1)^5*sgn(sin(-1/4*pi + 1/2*f*x + 1/2*e))) + sqrt(2)*(60*A 
*a^3*c^(49/2)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) - 1)/(cos(-1/4*pi + 1/2*f*x 
+ 1/2*e) + 1) - 900*B*a^3*c^(49/2)*(cos(-1/4*pi + 1/2*f*x + 1/2*e) - 1)...
 
3.2.7.9 Mupad [F(-1)]

Timed out. \[ \int \frac {(a+a \sin (e+f x))^3 (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{11/2}} \, dx=\int \frac {\left (A+B\,\sin \left (e+f\,x\right )\right )\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^3}{{\left (c-c\,\sin \left (e+f\,x\right )\right )}^{11/2}} \,d x \]

input
int(((A + B*sin(e + f*x))*(a + a*sin(e + f*x))^3)/(c - c*sin(e + f*x))^(11 
/2),x)
 
output
int(((A + B*sin(e + f*x))*(a + a*sin(e + f*x))^3)/(c - c*sin(e + f*x))^(11 
/2), x)